3y^2-((1-3y)/2)^2=2

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Solution for 3y^2-((1-3y)/2)^2=2 equation:



3y^2-((1-3y)/2)^2=2
We move all terms to the left:
3y^2-((1-3y)/2)^2-(2)=0
We add all the numbers together, and all the variables
3y^2-((-3y+1)/2)^2-2=0
We multiply all the terms by the denominator
3y^2*2)^2-((-3y+1)-2*2)^2=0
We add all the numbers together, and all the variables
3y^2*2)^2-((-3y+1)=0
Wy multiply elements
6y^3=0
We do not support eypression: y^3

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